Lipowsky Industrie Elektronik GmbH
Lipowsky Baby-LIN-3-RC LIN-Bus-Simulator
Lipowsky Baby-LIN-3-RC LIN-Bus-Simulator
Verfügbarkeit für Abholungen konnte nicht geladen werden
The Lipowsky Baby-LIN-II is a compact and cost-effective way to control LIN-Bus equipped devices with the help of a USB port of a standard computer. This controller features an integrated 32-bit microcontroller that is responsible for important tasks like LIN-bus protocol decoding and message scheduling. It comes with the LINWorks software suite that contains application programs, which along with a DLL, allows you to access the LIN-Bus of the controller. The LIN-Bus can also be accessed directly by the DLL-API that is easy to use and allows you to fetch or put frames, respective signals to the LIN-Bus.
One of the most unique features of Baby-LIN is that it can be powered either the USB port or from the LIN-Bus, allowing it to be as a standalone device, without a computer. The macro feature of this LIN-Bus allows it to store commands sequences, which can be later used for various tasks like, running an endless loop of tests on a LIN-equipped ECU.
The voltage provided at the LIN-Bus side can vary between 9 volts to 36 volts, and since the LIN-bus is isolated from the USB side, there are no electrical interference between the computer and on board electronics of the controller. The flash-based firmware storage of the Baby-LIN allows easy updates and changes of the LIN-bus specifications.
The LINWorks software suite that comes along with the Baby-LIN features various application programs. The LDF-Editor allows you to create, inspect, and edit LDFs. The Session Configurator allows you to define additional session parameters, like choosing which nodes should be available and which nodes should be simulated. It allows the Baby-LIN to play the role of both, master and slave nodes. The LIN-Bus can also work without any slave nodes, simulating all nodes at the same time.
Lipowsky Baby-LIN-3-RC LIN-Bus-Simulator
Frequently Asked Questions
Have a Question?
Be the first to ask a question about this.